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Critical tearing energy in a circumferentially-cracked circular cylinder of rubber under finite deformation
Authors:K N Morman Jr  K A Mazich  F G Oblinger  F Zhang  P C Killgoar Jr
Affiliation:(1) Scientific Research Laboratories, Ford Motor Company, Village Plaza, Suite 1100, 23400 Michigan Avenue, 48124 Dearborn, Michigan, USA;(2) Automated Analysis Corporation, 48104-6767 Ann Arbor, Michigan, USA
Abstract:In this paper the circumferentially-cracked cylindrical (CCC) specimen is subjected to both asymptotic and finite element analyses to determine its suitability for measuring the critical tearing energy, T c of rubber-like materials. When deformed axially, these specimens produce uniform radial crack deformation and extension along the circular crack front. The local/pointwise value of tearing energy along the crack front is also uniform and therefore identical to the tearing energy magnitude obtained by global measurement techniques such as the compliance method.Application of the CCC specimen is illustrated on a non-crystallizing rubber (SBR). Experimental results and non-linear finite element analysis are used to show that the CCC specimen yields a constant value of T c which is statistically independent of crack depth and the two sizes of the specimen used in the experiments. The CCC specimen represents an improvement over pre-cracked thin sheet specimens used for measuring T c where it has been demonstrated (see Mazich, et al. 2]), that crack extension along the crack front is pointwise non-uniform resulting in a globally measured value for critical tearing energy that is very dependent on specimen thickness and therefore different from the purportedly invariant material parameter T c. The asymptotic analysis yields an expression relating tearing energy, T, deformed crack-tip radius, rgr0, and material shear modulus, G of the form: % MathType!MTEF!2!1!+-% feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr% 4rNCHbGeaGak0Jf9crFfpeea0xh9v8qiW7rqqrFfpeea0xe9Lq-Jc9% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamivaiabg2% da9maalaaabaGaaG4maaqaaiaaiIdaaaGaeqiWdaNaam4raiabeg8a% YnaaBaaaleaacaaIWaaabeaaaaa!409C!\T = \frac{3}{8}\pi G\rho _0 \]. This expression yields numerical results which are in excellent agreement with the finite element predictions and test data.
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