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Welding of thin steel plates: a new model for thermal analysis
Authors:B V Kumar  O N Mohanty  A Biswas
Affiliation:(1) National Metallurgical Laboratory, 831 007 Jamshedpur, India;(2) Metallurgical Engineering, Indian Institute of Technology, 721 302 Kharagpur, India
Abstract:A mathematical model for the transient heat flow analysis in arc-welding processes is proposed, based on a unique set of boundary conditions. The model attempts to make use of the relative advantages of analytical as well as numerical techniques in order to reduce the problem size for providing a quicker solution without sacrificing the accuracy of prediction. The variation of thermo-physical properties with temperature has been incorporated into the model to improve the thermal analysis in the weld and heat-affected zones. The model has been evaluated using a five-point explicit finite difference method for analysing the welding heat flow in thin plates of two different geometric configurations. The temperature distribution closer to the heat source, primarily in the weld zone and the heat-affected zones, are predicted by the numerical technique. The thermal characteristics beyond the heat-affected zone are amenable to standard analytical techniques. The behaviour of the boundary condition in the model has been investigated in detail.Nomenclature qprime Rate of heat per unit thickness (Wm–1) - d Plate thickness (m) - v Velocity of source (m s–1) - t Time (s) - T Temperature value at the desired point (K) - T 0 Initial temperature (K) - K Thermal conductivity (W m–1 K–1) - rgr Density (kg m–3) - c p Specific heat (J kg–1 K–1) - agr Thermal diffusivity (m2 s–1) - n 
$$\frac{{q\prime \upsilon }}{{4\pi \alpha ^2 \rho c_{\text{p}} {\text{(}}T_{{\text{A}}_{{\text{e3}}} } {\text{ - }}T_0 {\text{)}}}}({\text{m}}^{{\text{ - 1}}} )$$
- xgr Distance of point considered from the source (xgr=x–vt) (m) - K 0 Modified Bessel function of second kind and zero order - r Radial distance from the source (r=(x 2+y 2)1/2) (m) - ohgr Model width (m) - a Plate width (m) - epsiv Distance from the source epsiv=(xgr2+4 ×10–4)1/2 (m) - mgrn 
$$\left {1 + \left( {\frac{{\tau n2\alpha }}{{va}}} \right)} \right]^{1/2} $$
Keywords:
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