Structure cristalline d'un phspho-tellurate de rubidium : Te(OH)6.Rb2HPO4.RbH2PO4

Te(OH)₆.Rb₂HPO₄.RbH₂PO₄ is monoclinic with_°: a = 12.26(1) b = 7.059(3) c = 8.225(3) A β = 90.32(5)° and Z = 2. The space group is $\text{P}\text{2}{}_1\text{a}$. Crystal structure has been solved by using 1093 independant reflexions with a final R value 0.051. As already observed in the first crystal structures of phospho-tellurates the main feature of this atomic arrangement is the coexistence of two different types of anions in the unit cell (PO₄ and Te(OH)₆ groups).